| World of KJ http://www.worldofkj.com/forum/ |
|
| Help with a math problem? http://www.worldofkj.com/forum/viewtopic.php?f=10&t=82329 |
Page 1 of 1 |
| Author: | zwackerm [ Thu Mar 16, 2017 10:32 am ] |
| Post subject: | Help with a math problem? |
If the odds of event A happening are 98/100, the odds of event B happening are 999/1000, and the odds of event C happening are 21/28, what are the odds of none of the events happening? |
|
| Author: | Alex Y. [ Thu Mar 16, 2017 11:05 am ] |
| Post subject: | Re: Help with a math problem? |
(1-(98/100))*(1-(999/1000)*(1-(21/28)) |
|
| Author: | zwackerm [ Thu Mar 16, 2017 11:53 am ] |
| Post subject: | Re: Help with a math problem? |
That would be .24. Definitely wrong. |
|
| Author: | Shack [ Thu Mar 16, 2017 12:15 pm ] |
| Post subject: | Re: Help with a math problem? |
Instead of multiplying the chance of each happening you multiply the chance of each not happening Event A = 2/100 or .02 Event B = 1/1000 or .001 Event C = 7/28 or .25 .02 * .001 * .25 = .000005 |
|
| Author: | _axiom [ Thu Mar 16, 2017 12:28 pm ] |
| Post subject: | Re: Help with a math problem? |
Shack wrote: Instead of multiplying the chance of each happening you multiply the chance of each not happening Event A = 2/100 or .02 Event B = 1/1000 or .001 Event C = 7/28 or .25 .02 * .001 * .25 = .000005 That's what Alex wrote. zwackerm just didn't put it in the calculator as he should've. |
|
| Author: | zwackerm [ Thu Mar 16, 2017 1:18 pm ] |
| Post subject: | Re: Help with a math problem? |
Shack wrote: Instead of multiplying the chance of each happening you multiply the chance of each not happening Event A = 2/100 or .02 Event B = 1/1000 or .001 Event C = 7/28 or .25 .02 * .001 * .25 = .000005 Thanks Shack and Alex! Sorry I misread your answer. |
|
| Page 1 of 1 | All times are UTC - 5 hours [ DST ] |
| Powered by phpBB © 2000, 2002, 2005, 2007 phpBB Group http://www.phpbb.com/ |
|